Chemistry Lab

Title: response of Carboxylic Acids
Objective: To Determine The Reaction of Carboxylic Acids
Procedure: As referred to Lab manual.

Results:

A. Salt Formation

| tangled |Solvent |Solubility |
|Benzoic Acid |Cold peeing |Partially soluble |
|Benzoic Acid |10 % NaOH |soluble |

B. Salt Hydrolysis
Sodium acetate solution changed the color of litmus from red to blue.
C. Reaction With Sodium Carbonate
Observation : A corporation of gas bubbles was released.
D. Esterification
Ethanol : Fruity smell Isopentanol : Fruity smell
Questions:
1. drop a line an equation that accounts for the solubility of benzoic blistery in aqueous base.
(C6H5)COOH + OH- ? (C6H5)COO- + H2O
2.



What would you expect to happen if a solution of atomic number 11 benzoate was acidified? save an equation.
If a solution of sodium benzoate was acidified, Na in sodium benzoate solution leave alone displaced by the H+ from the acid and olibanum producing benzoic acid.
(C6H5)COO-Na+ + H2O/H+ ? (C6H5)COOH + Na+ + OH-
3. Use your answers to Questions 1 and 2 to explain how a water-insoluble perfect acid office be freed of non-acidic impurities.
Water-insoluble organic acid can be freed of non-acidic impurities by adding strong base into it during fractional distillation. The water-insoluble organic acid will react with the strong to produce an ionic salt which is soluble in water. On the other hand, water-insoluble organic acid which are slightly soluble in water can be extracted by aqueous base from solution in an organic solvent. The fact that organic acid are weak acids and sole(prenominal) partially dissociates in water will cause the acid to be freed of non-acidic impurities. The salt solutions are alkaline.
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